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c语言猜灯谜,猜灯谜的灯笼怎么做

c语言猜灯谜?public static void main(String[]args){ Scanner sc=new Scanner(System.in);int x=(int)(Math.random()*100);//生成一个0~100的随机数 int y=-1;System.out.println("已生成0~100的随机整数,那么,c语言猜灯谜?一起来了解一下吧。

猜灯谜谜语大全及答案趣味

#include<stdio.h>

#include<stdlib.h>

#include<time.h>

void main()

{

srand(int(time(NULL)));

int putnum=rand()%100;

int yournum;

printf("请猜数字:\n");

while((scanf("%d",&yournum),yournum)!=putnum)

{

if(yournum>putnum)

{

printf("哈哈,大了!!!\n");

}

else

{

printf("真吝啬,给这么小!!!\n");

}

}

printf("哇,真聪明,给爷笑一个!!!!!!\n");

}

猜灯谜的谜题

#include <time.h>

#include <stdio.h>

#include <stdlib.h>

#define UI unsigned short int

void game()

{

UI answer;

UI input;

UI lower=1;

UI upper=100;

UI count=0;

srand(time(NULL));

do{answer=rand()%101;}

while(answer==0);

puts("Welcome to the number guessing game!");

do

{

puts("Please enter an integer from 1 to 100 (again):");

scanf("%lu",&input);

getchar();

count=count+1;

if(input==answer){puts("You succeeded!");printf("The number of time(s) you entered is %lu.\n",count);}

else

{

puts("You failed!");

if(input<answer){if(input>lower){lower=input;}puts("The answer is greater than your input.");}

else{if(input<upper){upper=input;}puts("The answer is less than your input.");}

printf("The answer is from %lu to %lu.\n",lower,upper);

}

}

while(input!=answer);

}

#undef UI

int main()

{

game();

system("Pause");

return 0;

}

猜灯谜代码

1098-989=109

A=1

B=0

C=9

D=8

程序如下

function Main

for a=0 to 9

for b=0 to 9

for c=0 to 9

for d=0 to 9

i = a*1000+b*100+c*10+d

j = c*100+d*10+c

k = a*100+b*10+c

if i-j=k then

ShowInfo(i&"-"&j&"="&k)

endif

next

next

next

next

endfunc

猜灯谜的灯笼怎么做

一个函数用于生成一个随机数

再用一个函数进行三次循环

如果循环中输入的数字猜对了就返回1如果三次循环结束则返回0

主数字判断返回的结果如果是1则表示猜对否则表示猜错

然后询问是否继续进行猜数字游戏

下面是一个简单的代码

#include<stdio.h>

#include<time.h>

voidclean_input_buf(void)

{

while(getchar()!='\n');

}

intmake_num(intnum)

{

srand(num);

return1+rand()%20;

}

intguess_num(void)

{

inti=3;

intn;

intnum;

num=make_num(clock());

while(i)

{

printf("请输入一个你猜的数字:");

scanf("%d",&n);

if(n==num)

return1;

clean_input_buf();

--i;

}

return0;

}

intmain(intargc,char**argv)

{

charc;

printf("猜数字游戏!\n游戏要猜测的数字为1-20,每个数字可以猜测3次!\n");

while(1)

{

if(guess_num()==1)

printf("恭喜你,你猜中了!\n");

else

printf("很遗憾,你猜错了!\n");

redo:

printf("还要继续游戏吗?继续输入Y否则输入N!\nY/N:");

c=getchar();

clean_input_buf();

if(c=='Y'||c=='y')

continue;

elseif(c=='N'||c=='n')

break;

else

{

printf("输入错误,请重新输入!\n");

gotoredo;

}

}

return0;

}

猜灯谜 谜语

很简单啦

#include<stdio.h>

#include<time.h>

#include <stdlib.h>

char start()

{

return rand()%26+97;

}

void big()

{

printf("有点大哦 继续吧\n");

}

void small()

{

printf("有点小 继续吧\n");

}

bool newcase()

{

printf("敢不敢重新来一次哦?(Y:是的 N:不干啦)\n");

char tmpselect;

scanf("%c",&tmpselect);

getchar();

if(tmpselect == 'Y')

{

return true;

}

else

{

return false;

}

}

int main()

{

while (1)

{

srand((int)time(0));

char TheTarget =start();

char TheGuess;

bool restart=false;

while(restart)

{

printf("竞猜竞猜 输入猜猜\n");

scanf("%c",&TheGuess);

getchar();

if (TheGuess==TheTarget)

{

printf("你运气好!成功了\n");

restart = newcase();

if(restart)

{

break;

}

else

{

exit(0);

}

}

if (TheGuess>TheTarget)

{

big();

}

else

{

small();

}

}

}

}

以上就是c语言猜灯谜的全部内容,); return -1; } i = getrand(); if (j != i) k ++; printf("随机出的数字为%d,你猜的数字为%d,内容来源于互联网,信息真伪需自行辨别。如有侵权请联系删除。

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